In celestial mechanics the specificangular momentum plays a pivotal role in the analysis of the two-body problem. One can show that it is a constant vector for a given orbit under ideal conditions. This essentially proves Kepler's second law. It's called specific angular momentum because it's not the actual angular momentum, but the angular momentum per mass. Thus, the word "specific" in this term is short for "mass-specific" or divided-by-mass: Thus the SI unit is: m2·s−1. denotes the reduced mass.
Proof that the specific relative angular momentum is constant under ideal conditions
Prerequisites
The following is only valid under the simplifications also applied to Newton's law of universal gravitation. One looks at two point masses and, at the distance from one another and with the gravitational force acting between them. This force acts instantly, over any distance and is the only force present. The coordinate system is inertial. The further simplification is assumed in the following. Thus is the central body in the origin of the coordinate system and is the satellite orbiting around it. Now the reduced mass is also equal to and the equation of the two-body problem is with the standard gravitational parameter and the distance vector that points from the origin to the satellite, because of its negligible mass. It is important not to confound the gravitational parameter with the reduced mass, which is sometimes also denoted by the same letter.
Proof
One obtains the specific relative angular momentum by multiplying the equation of the two-body problem with the distance vector The cross product of a vector with itself is 0. The left hand side simplifies to according to the product rule of differentiation. This means that is constant. And this is exactly the angular momentum per mass of the satellite: This vector is perpendicular to the orbit plane, the orbit remains in this plane because the angular momentum is constant. One can obtain further insight into the two-body problem with the definitions of the flight path angle and the transversal and radial component of the velocity vector. The next three formulas are all equivalent possibilities to calculate the absolute value of the specific relative angular momentum vector
The proof starts again with the equation of the two-body problem. This time one multiplies it with the specific relative angular momentum The left hand side is equal to the derivative because the angular momentum is constant. After some steps the right hand side becomes: Setting these two expression equal and integrating over time leads to Now this equation is multiplied with and rearranged Finally one gets the orbit equation which is the equation of a conic section in polar coordinates with semi-latus rectum and eccentricity. This proves Kepler's first law, in words:
Second law
The second law follows instantly from the second of the three equations to calculate the absolute value of the specific relative angular momentum. If one connects this form of the equation with the relationship for the area of a sector with an infinitesimal small angle , the equation comes out, that is the mathematical formulation of the words:
Third law
Kepler's third is a direct consequence of the second law. Integrating over one revolution gives the orbital period for the area of an ellipse. Replacing the semi-minor axis with and the specific relative angular momentum with one gets There is thus a relationship between the semi-major axis and the orbital period of a satellite that can be reduced to a constant of the central body. This is the same as the famous formulation of the law: