A total of 4,000,000 Thai baht was awarded to the winner of the event, with a total prize fund of 10,500,000 baht. The championships were sponsored by Thai rum producers SangSom. The breakdown of prize money is shown below.
Winner: 4,000,000 baht
Runner-up: 1,300,000 baht
Semi-finalists: 750,000 baht
Quarter-finalists: 375,000 baht
Last 16: 150,000 baht
Third in group: 75,000 baht
Fourth in group: 50,000 baht
Total: 10,500,000 baht
Tournament summary
The 2019 Six-red World Championship was a professional pro–am invitational snooker event held between 2 and 7 September 2019. The championship was contested under the six-red variant of snooker, with only six reds being used instead of the traditional fifteen. Invited players first competed in round-robin groups of four, the top two from each group progressing to a knockout round. The knockout rounds were first contested as best-of-11-frames matches up until the semi-final, which were played as best-of-13-frames, and the final played as best-of-15-frames.
Group stages
The 32 invited players were split into eight groups of four players, with best-of-9-frame matches. Defending champion Kyren Wilson progressed alongside Thailand's amateur player Passakorn Suwannawat in group A. Suwannawat defeated Wilson during the group stage 5–2, leaving Wilson to have to defeat Mohammed Shehab to progress in the final group match. Stephen Maguire won all three of his group games in group B, with amateur player Wu Yize in second place. Wu won only one game in the group, but finished above Luca Brecel on frame difference. Ding Junhui finished above Joe Perry after a 5–3 win in group C with both progressing. The group also contained one of two female players in Reanne Evans, and Noppon Saengkham. Gary Wilson defeated three-time world championMark Selby 5–4 in the second round of matches to progress. Selby joined Wilson after defeating Sunny Akani 5–2. The 2019 Riga Masters champion Yan Bingtao finished second in group E, despite being whitewashed by John Higgins 5–0, who won the group, after winning all three group games. David Gilbert won group F ahead of 2019 World Seniors Championship winner Jimmy White in second. White defeated amateur player Mohamed Khairy 5–2 to progress. Stuart Bingham, the 2015 world champion won group G, only losing four frames in the three matches. Bingham progressed with Ali Carter in second place. Mark Williams won group H after defeating 2006 world championGraeme Dott 5–4. Dott joined Williams in the knockout round after a defeat of Thailand's Thepchaiya. made the only maximum break of the event during the match.
Knockout rounds
The knockout portion of the event was contested over four rounds, starting 5 September, with the final played 7 September 2019. In total, three former winners of the event progressed into the quarter-finals. Mark Williams, winner in 2017 defeated Joe Perry 6–1 and 2016 winner Ding Junhui defeated Graeme Dott 6–4. The 2014 winner Stephen Maguire defeated Jimmy White 6–5 despite being behind at 3–5, and won the match on the final. However, defending champion Kyren Wilson lost in his match against David Gilbert 4–6. The sole remaining Thai player Passakorn Suwannawat lost in the last 16 to Ali Carter 5–6. Elsewhere, Stuart Bingham defeated Mark Selby 6–2, Gary Wilson defeated Yan Bingtao on a 6–5, and John Higgins defeated Wu Yize 6–4. The first quarter-final saw Stephen Maguire defeat Ali Carter 6–2. Gary Wilson played Ding Junhui with the winner to play Maguire. Ding led 5–4, and had Wilson requiring snookers, but still lost the match 5–6. In a rematch of the 2019 World Snooker Championship semi-final, Dave Gilbert played John Higgins in the quarter-final. Higgins defeated Gilbert 6–4 to progress to the semi-finals. After taking all of the first four frames, Mark Williams defeated Stuart Bingham 6–3 to set up a rematch of the 2018 World Snooker Championship final against Higgins. Maguire won the first semi-final over Wilson, 7–5. Higgins defeated Williams by the same scoreline to meet Maguire in the final. The final was played on 7 September 2019, as a best-of-15-frames match. The match was contested between two players who had formed the winning Scotland pair at the 2019 World Cup, Maguire and Higgins. Maguire had won the event previously, in 2014, where he had defeated Ricky Walden in the final. Maguire took the first three frames, before Higgins led winning the next four frames. Maguire won both frame eight, and frame nine on the final black to lead 5–4. Maguire won the tenth frame and Higgins the eleventh. Higgins made the only 50+ break of the match to tie at 6–6. Maguire won the next two frames to win the match, and the championship 8–6. Maguire commented that he was "lucky" to win the tournament, but the result still "felt good". The win was Maguire's first singles tournament victory since the 2014 Lisbon Open.
Results
Group stage
The tournament was split into two sections, with a round-robin group stage, followed by a single-elimination tournament. There were a total of eight groups of four, played from 2 to 4 September. The top two players from each group qualified for the knock-out stage with all matches being played as best-of-nine-frames. Positions within the group were decided by the number of matches won and then, in the event of a tie, by frame difference. Where two players were still tied, the result of the match between them determined their positions. Where three players were still tied, the top position was determined by a draw and the other two positions by the result of the match between those two players.
The last 16 matches and quarter-finals were played on 5 September, the semi-finals on 6 September and the final on 7 September. Players in bold denote match winners.
Final
The final was played as a best-of-15-frames match, on 7 September 2019. Scores in bold denote the winner of the frame, whilst a score in brackets denotes a break of over 50.
Maximum breaks
A maximum break in six-red snooker is 75. Only one maximum break was scored at the event, by Thepchaiya.
